educationalera

  • Increase font size
  • Default font size
  • Decrease font size

Problems on Trains Objective Question with answer

AddThis Social Bookmark Button

1.) A train 100 m long is running at the speed of 30 km / hr. find the time taken by it to pass a man standing near the railway line.

A. 12 sec          B. 23 sec

C. 16 sec          D. None of these

View Answer

Answer: Option A
Explanation:

Speed of the train = (30 x 5/18) m / sec = (25/3) m/ sec.

Distance moved in passing the standing man = 100 m.

Required time taken = 100/ (25/3) = (100 *(3/25)) sec = 12 sec

2.) A train is moving at a speed of 132 km/br. If the length of the train is 110 meters, how long will it take to cross a railway platform 165 meters long?

A. 8½ sec                   B.

C. 5 3/2                      D. None of these

View Answer

Answer: Option B
Explanation:

Sol. Speed of train = 132 *(5/18) m/sec = 110/3m/sec.

Distance covered in passing the platform = (110 + 165) m = 275 m.

Time taken =275 *(3/110) sec =15/2 sec = 7½ sec

3.) A man is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the length of the train and its speed?

A. 42 km           B. 54 km

C. 66 km           D. None of these

View Answer

Answer: Option B
Explanation:

Let the length of the train be x meters,

The train covers x meters in 8 seconds and (x + 180) meters in 20 sec

X/8=(x+180)/20 ó 20x = 8 (x + 180) <=>      x = 120.

Length of the train = 120 m.

Speed of the train = (120/8) m/sec = m/sec = (15 *18/5) kmph = 54 km

4.) A train 150 m long is running with a speed of 68 kmph. In what time will it pass a man who is running at 8 kmph in the same direction in which the train is going?

A. 9 sec            B. 13 sec

C. 16 sec          D. None of these

View Answer

Answer: Option A
Explanation:

Speed of the train relative to man = (68 - 8) kmph

= (60* 5/18) m/sec = (50/3) m/sec

Time taken by the train to cross the man

= Time taken by it to cover 150 m at 50/3 m/sec = 150 *3/ 50 sec
= 9 sec

5.) A train 220 m long is running with a speed of 59 kmph. In what will it pass a man who is running at 7 kmph in the direction opposite to that in which the train is going?

A. 12 sec          B. 23 sec

C. 16 sec          D. 31 sec

View Answer

Answer: Option A
Explanation:
Speed of the train relative to man = (59 + 7) kmph

= 66 *5/18 m/sec = 55/3 m/sec.

Time taken by the train to cross the man

= Time taken by it to cover 220 m

at (55/3) m / sec = (220 *3/55) sec = 12 sec

 
  • «
  •  Start 
  •  Prev 
  •  1 
  •  2 
  •  3 
  •  Next 
  •  End 
  • »
JPAGE_CURRENT_OF_TOTAL


Oracle Certification

oracle_logo

The Oracle Certification Program is a professional certification program offered by the Oracle Corporation. There are three levels of Oracle Certification in several disciplines: Oracle Certified Associate (OCA), Oracle Certified Professional (OCP), and Oracle Certified Master (OCM).

Java Certification

java_logo

Sun Certified Professional (SCP) is a professional certification program by Sun Microsystems, a subsidiary of Oracle Corporation. There are two levels of java Certification in several disciplines: Sun Certified Java Associate (SCJA), Sun Certified Java Programmer (SCJP), and Sun Certified Java Developer (SCJD)

Red Hat Certification

red_hat_logo

The Red Hat Certification Program is Red Hat's professional certification program for Red Hat and general Linux related skills such as system administration on Red Hat Enterprise Linux Red Hat Certified Technician (RHCT)  and Red Hat Certified Engineer (RHCE)