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Times on Work Question and answer

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1) It was calculated that 75 men could complete a piece of work in 20 days.When work was scheduled to commence, it was found necessary to send 25 men to another project. How much longer will it take to complete the work? 

A.      20                               B.    30

C.      40                               D.    None of these

View Answer

Answer: Option B
Explanation:
Before:
One day work = 1 / 20
One man’s one day work = 1 / (20 * 75)
Now:
No. Of workers = 50
One day work = 50 * 1 / (20 * 75) 
The total no. of days to complete the work = (75 * 20) / 50 = 30


2) A student divided a number by 2/3 when he required to multiply by 3/2. Calculate the percentage of error in his result.

A.   0 %                              B. 10 %

C.   5%                               D. None of these

View Answer

Answer: Option A

Explanation:
Since 3x / 2 = x / (2 / 3)


3) A dishonest shopkeeper professes to sell pulses at the cost price, but he uses a false weight of 950gm. for a kg. His gain is …%.

A. 4.26 %                              B. 3.40 %

C. 5.26 %                              D. None of these

View Answer

Answer: Option C
Explanation:
He sells 950 grams of pulses and gains 50 grams.
If he sells 100 grams of pulses then he will gain (50 / 950) *100 =5.26

4) A software engineer has the capability of thinking 100 lines of code in five minutes and can type 100 lines of code in 10 minutes. He takes a break for five minutes after every ten minutes. How many lines of codes will he complete typing after an hour?

A.  100                              B. 180

C.  200                              D. 250

View Answer

Answer:
Option D
250 lines of codes

5) A man was engaged on a job for 30 days on the condition that he would get a wage of Rs. 10 for the day he works, but he have to pay a fine of Rs. 2 for each day of his absence. If he gets Rs. 216 at the end, he was absent for work for ... days.

A. 7 days                                 B. 11 days

C. 18 days                               D. None of these

View Answer

Answer: Option A
Explanation:
The equation portraying the given problem is:
10 * x – 2 * (30 – x) = 216 where x is the number of working days.
Solving this we get x = 23
Number of days he was absent was 7 (30-23) days.

6) A contractor agreeing to finish a work in 150 days, employed 75 men each working 8 hours daily. After 90 days, only 2/7 of the work was completed. Increasing the number of men by ________ each working now for 10 hours daily, the work can be completed in time.

A. 80 men                                B. 124 men

C. 150 men                              D. None of these

View Answer

Answer: Option C.
Explanation:
One day’s work = 2 / (7 * 90)
One hour’s work = 2 / (7 * 90 * 8)
One man’s work = 2 / (7 * 90 * 8 * 75)
The remaining work (5/7) has to be completed within 60 days, because
the total number of days allotted for the project is 150 days.
So we get the equation
(2 * 10 * x * 60) / (7 * 90 * 8 * 75) = 5/7 where x is the number of
men working after the 90th day.
We get x = 225
Since we have 75 men already, it is enough to add only 150 men.


 
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